更新时间:2023-02-20 来源:黑马程序员 浏览量:
下面是一个基于Java多线程的赛马游戏示例,该示例中有5匹赛马,每匹赛马都是一个线程。每匹赛马都有一个速度和一个起跑线的位置,他们将在屏幕上移动,直到达到终点线。
import java.util.Random;
public class Horse implements Runnable {
private static int counter = 0;
private final int id = counter++;
private int strides = 0;
private static Random rand = new Random();
private static final int FINISH_LINE = 75;
private Race race;
public Horse(Race race) {
this.race = race;
}
public synchronized int getStrides() {
return strides;
}
@Override
public void run() {
try {
while(!Thread.interrupted()) {
synchronized(this) {
strides += rand.nextInt(3);
}
Thread.sleep(200);
race.printHorses();
if(strides >= FINISH_LINE) {
race.win(this);
return;
}
}
} catch(InterruptedException e) {
System.out.println("Horse " + id + " interrupted");
}
}
@Override
public String toString() {
return "Horse " + id;
}
}
public class Race {
private Horse[] horses;
private int numHorses;
private static final int FINISH_LINE = 75;
private volatile Horse winner;
public Race(int numHorses) {
this.numHorses = numHorses;
horses = new Horse[numHorses];
for(int i = 0; i < numHorses; i++) {
horses[i] = new Horse(this);
}
}
public void startRace() {
System.out.println("Starting the race...");
for(Horse horse : horses) {
new Thread(horse).start();
}
}
public void win(Horse horse) {
synchronized(this) {
if(winner == null) {
winner = horse;
System.out.println("Winner: " + winner);
}
}
}
public void printHorses() {
for(int i = 0; i < 10; i++) {
System.out.println();
}
for(int i = 0; i < numHorses; i++) {
System.out.print(horses[i] + ": ");
for(int j = 0; j < horses[i].getStrides(); j++) {
System.out.print("*");
}
System.out.println();
}
try {
Thread.sleep(15);
} catch(InterruptedException e) {
System.out.println("Interrupted while printing horses");
}
}
}
public class RacingGame {
public static void main(String[] args) {
Race race = new Race(5);
race.startRace();
}
}
在这个示例中,每匹马都有一个随机生成的速度,每次移动一定的步数。每匹马都有一个起跑线的位置,当它们越过终点线时,会触发一个“胜利”的方法,并且在控制台上输出获胜马匹的信息。
在'Race'类中,'startRace()'方法启动每个马匹线程,每个线程都运行一个'Horse'。